# Solution For Baseball Game

The Baseball Game problem on LeetCode is a simple problem that involves simulating a baseball game and calculating the total score of a player. Here is a detailed solution to the problem:

Problem Description:
You are keeping score for a baseball game with strange rules. The game consists of several rounds, where the scores of each round are represented by a list of strings.
The valid options for a score are:
1. An integer, which represents the number of points earned in this round.
2. “+” which represents the number of points earned in this round as the sum of the last two valid round scores.
3. “D” which represents the number of points earned in this round as twice the last valid round score.
4. “C” which represents the removal of the last valid round score.

You need to return the total score of the player after all the rounds.

Solution:
To solve this problem, we will use a stack to keep track of the valid scores. For each score in the list of scores, we will perform the following actions:

1. If the score is an integer, push it onto the stack and add it to the running total of the score.
2. If the score is “+”, pop the last two scores from the stack, sum them, and push the sum onto the stack. Then add the sum to the running total of the score.
3. If the score is “D”, double the last score in the stack, push the double onto the stack, and add it to the running total of the score.
4. If the score is “C”, pop the last score from the stack and subtract it from the running total of the score.

After iterating through all the scores, the running total of the score will be the total score of the player.

Here is the Python implementation of the above solution:

def calPoints(self, ops: List[str]) -> int:
stack = [] score = 0
for op in ops:
if op.isdigit() or op == “-“:
stack.append(int(op))
score += int(op)
elif op == “+”:
last1 = stack.pop()
last2 = stack.pop()
curr = last1 + last2
stack.append(last2)
stack.append(last1)
stack.append(curr)
score += curr
elif op == “D”:
last = stack.pop()
curr = 2 * last
stack.append(last)
stack.append(curr)
score += curr
elif op == “C”:
last = stack.pop()
score -= last
return score

Time Complexity:
The time complexity of this solution is O(n) where n is the number of scores.

Space Complexity:
The space complexity of this solution is also O(n) as we are using a stack to keep track of the valid scores.

Overall, this is an efficient solution to the Baseball Game problem on LeetCode.

## Step by Step Implementation For Baseball Game

```You can create a class named BaseballGame with a method named calPoints which takes an array of strings as input.

The input will be in the format ["5", "2", "C", "D", "+"] where each string is either a number, "C", "D", or "+". Numbers represent the number of points scored and "C" represents a caught foul, "D" represents a dropped foul, and "+" represents a point scored by hitting a home run.

You can assume that all input is valid and that each game consists of only one inning.

Your method should return the total number of points scored in the game.

Here is an example input and output:

Input: ["5","2","C","D","+"]
Output: 30

Explanation:
5 points for hitting a home run
2 points for hitting a double
Caught foul worth 3 points
Dropped foul worth 1 point
3 points for hitting a home run

So the total score for this game is 30 points.```
```You're given an array of strings, where each string is a record of a player's name and their respective batting average. e.g. for the first player in the array their name would be "player1" and their batting average would be "0.333".

You're required to calculate the player's "slugging percentage". This is defined as the number of bases a player earns per at-bat, averaged over the course of all at-bats.

A single at-bat can earn the player 0, 1, 2, 3, or 4 bases. If the player hits a home run, they automatically earn 4 bases. If they hit a triple, they earn 3 bases. If they hit a double, they earn 2 bases. If they get on base (e.g. via a hit, walk, or hit-by-pitch), they earn 1 base. If they make an out, they earn 0 bases.

The slugging percentage is calculated by taking the total number of bases a player earns and dividing it by the number of at-bats they have.

For example, consider the following array of player records:

player1 0.333
player2 0.500
player3 0.100

player1 has 1 at-bat and earned 1 base, so their slugging percentage is 1.0.
player2 has 2 at-bats and earned 4 bases, so their slugging percentage is 2.0.
player3 has 10 at-bats and earned 0 bases, so their slugging percentage is 0.0.

Write a function that takes in an array of player records and calculates the slugging percentage for each player, rounded to the nearest 3 decimal places.

def slugging_percentage(player_records):

player1 = {"name": "player1", "avg": 0.333}
player2 = {"name": "player2", "avg": 0.500}
player3 = {"name": "player3", "avg": 0.100}

player_records = [player1, player2, player3]

for player in player_records:

name = player["name"]
avg = player["avg"]

# calculate slugging percentage

# print results

print(name + ": " + str(slugging_percentage))```
```/**
* @param {string[]} ops
* @return {number}
*/
var calPoints = function(ops) {
let stack = []

for(let i = 0; i < ops.length; i++) {
if(ops[i] === '+') {
stack.push(stack[stack.length - 1] + stack[stack.length - 2])
} else if(ops[i] === 'D') {
stack.push(2 * stack[stack.length - 1])
} else if(ops[i] === 'C') {
stack.pop()
} else {
stack.push(parseInt(ops[i]))
}
}

return stack.reduce((a, b) => a + b, 0)
};```
```You can use any programming language.

You can use any data structures.

Your code should compile and run.

Your code should be error free.

Your code should produce the correct results.

Your code should use the least amount of memory possible.

Your code should run in the shortest amount of time possible.

Your code should be easy to modify and extend.

Your code should be easy to maintain.```
```You can use Stack data structure to keep track of the scores.

Stack scores = new Stack();

// Iterate through the given array
foreach (int score in input)
{
// If the score is a valid number, push it onto the stack
if (score >= 0 && score <= 10)
{
scores.Push(score);
}
// If the score is "C", remove the top element from the stack
else if (score == "C")
{
scores.Pop();
}
// If the score is "D", double the top element of the stack and add it to the second top element
else if (score == "D")
{
int top = scores.Pop();
scores.Push(top * 2);
scores.Push(top);
}
// If the score is "+", add the top two elements of the stack and push the result onto the stack
else if (score == "+")
{
int top1 = scores.Pop();
int top2 = scores.Pop();
scores.Push(top1 + top2);
scores.Push(top1);
scores.Push(top2);
}
}

// Sum up all the scores in the stack
int sum = 0;
foreach (int score in scores)
{
sum += score;
}

return sum;```

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