Fizz Buzz - Leetcode Solution

The FizzBuzz problem on Leetcode is a simple programming exercise that requires you to output a sequence of numbers, replacing certain numbers with "Fizz" or "Buzz" depending on whether they are divisible by 3 or 5, respectively.

Algorithm:

1. Start a loop that iterates from 1 to n.
2. For each iteration, check if the current number is divisible by both 3 and 5. If so, print "FizzBuzz".
3. If the current number is only divisible by 3, print "Fizz".
4. If the current number is only divisible by 5, print "Buzz".
5. If the current number is not divisible by either 3 or 5, print the number itself.

Code in Python:

for i in range(1, n+1):
    if i % 3 == 0 and i % 5 == 0:
        print("FizzBuzz")
    elif i % 3 == 0:
        print("Fizz")
    elif i % 5 == 0:
        print("Buzz")
    else:
        print(i)

The above code iterates through numbers from 1 to n, and for each number it checks if it is divisible by 3, 5 or both. Based on the condition, it prints either "Fizz", "Buzz", "FizzBuzz" or the number itself.

This solution is efficient as it only requires one loop to iterate through all the numbers and all the conditions are checked within the loop. It also follows the algorithm mentioned earlier and produces the correct output for all values of n.

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